Hitung : Panjang AB
Diket: AB=AC BC=50cm Sin b = Sin c
Sudut a1= 90 BD=36cm
jawab: (AD/Sin b) = (BD/Sin a1) (AD/Sin b) = (36/Sin 90)
(AD/Sin b) = 36
Karena Sin b= Sin c "Maka: ..."
(AD/Sin c) = (CD/Sin a2) 36 = (14/Sin a2)
Sin a2 = (14/16)
a2 = 22.885
Sudut b = (180 – 22.886 – 90)/2
= 33.5575
Sudut d segi tiga ABD = 180 – 33.5575 – 90
= 56.4425
(AB/Sin d1)=(36/Sin a1)
AB=Sin d1*36/Sin a1
AB=(Sin 56.4425)*36/Sin90
AB= 0.8333 * 36 / 1
AB=29.9999 = 30cm
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